x^2-800x+80000=0

Solution for x^2-800x+80000=0 equation:

x^2-800x+80000=0

a = 1; b = -800; c = +80000;
Δ = b2-4ac
Δ = -8002-4·1·80000
Δ = 320000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320000}=\sqrt{160000*2}=\sqrt{160000}*\sqrt{2}=400\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-800)-400\sqrt{2}}{2*1}=\frac{800-400\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-800)+400\sqrt{2}}{2*1}=\frac{800+400\sqrt{2}}{2}
$